Of distance he travels and the amount of time Gaining at the same rate it's exactly the reverse, makes sense. He's gaining velocity at the same rate, since it's Meter per second squared rate and when his falling down, Reverse of that you know why? Because while he's going up, he's losing velocity at 10 To be the exact reverse of his downward motion. Solving this entire question you see, when Spiderman is going up his upward motion is going Than that but how much? Well, here's the secret to Takes for him to go up and come back down we want to calculate how much time it takes only to go up. Velocity is decreasing so it's negative 10, but the big question is what is the time? Is it eight seconds? No, that's the time it Point he's at rest, isn't it? After that he starts coming back down he starts speeding up downwards, right? So we know it's final velocity zero we know the acceleration, We know the final velocity, that is zero why is the final velocity zero? Because at the top most So we only consider from here to here so let's see what's given to us so in that we need to calculate what the initial velocity is. We are going to consider Spiderman jumping all the way up like this and coming to rest at the top most point after that he comes back down. So it makes sense to thinkĪbout his upward motion, right? So that's the first thing so let's only consider the upward motion, upward motion which means So we cannot consider the total motion because during one motionĪcceleration is negative and during the other motion the acceleration becomes positive which means we have to either consider the upward motion separately or the downward motion separately only then we can apply theĮquations of motion, right? So the first question we need to ask is which motion should we consider? The upward motion or the downward motion? Well, look at what is asked we are asked calculate the Spiderman is coming back down his velocity increases heīecomes faster and faster and during that time, theĪcceleration becomes positive. What's the problem over there? The problem is when Spider-Man is going up he's slowing down and during that time, hisĪcceleration becomes negative because it's becoming slower and slower. But the difference over here is that Spiderman goes both up and comes back down and that total time is given to us. Up, so how do we do this? Well, because objects in free-fall always have a constant acceleration this means we can go ahead and use the three equations of motion and solve what we want and we've solved problems like this in a previous video calledįree-fall one body soul example. Seconds for him to go up and come back down and we are asked to calculate the velocity with which he jumped up. Jump straight up like this goes up and then lands back and it takes him eight So what's given to us, well, it's given that we have Spiderman so here's our Spiderman. With which he jumped up given g is 10 meters per second square. Spiderman jumps straight upĪnd lands back in eight seconds calculate the velocity Solve a couple of problems of objects in free fall but when they're both going up and down, here's the first example.
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